30y^2+60y=1050

Solution for 30y^2+60y=1050 equation:

30y^2+60y=1050

We move all terms to the left:

30y^2+60y-(1050)=0

a = 30; b = 60; c = -1050;
Δ = b2-4ac
Δ = 602-4·30·(-1050)
Δ = 129600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{129600}=360$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-360}{2*30}=\frac{-420}{60}
=-7
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+360}{2*30}=\frac{300}{60}
=5
$